Comments on: Using AWK to remove file extensions

By: Carlo

Carlo — Wed, 01 Aug 2007 12:20:45 +0000

@anonymous:
this is the reason I wrote

it’s definitely easy to achieve it if your files have just a “.” in their names

Anyway, your problem could be solved with
for i in $(ls *.txt.old | awk -F "." '{print $1}'); do mv $i.txt.old $i.txt; done

By: anonymous

anonymous — Wed, 01 Aug 2007 11:41:20 +0000

Ahh, but what if you have files like "file.txt.old"

Then you are somewhat stuffed, as the extention gets defined to be .txt.old, rather than .old?

By: Carlo

Carlo — Wed, 11 Apr 2007 12:42:49 +0000

Booger:
Good
A solution to your problem could be:
l *.sd *.sb -1 | awk -F "." '{print $1}' | uniq -c | awk '$1=="1" {print $2}'

By: Booger

Booger — Tue, 10 Apr 2007 18:21:10 +0000

this is great - i don’t think “tannoiser” understands how an example should illustrate a concept with an easy example so that you can modify it to real needs. In particular, I use a compiler that compiles xyz.sd into xyz.sb. So on a directory of 1000 .sd’s the easiest way to find the 3 that don’t compile is to list all of the .sds and .sbs, remove the extensions and do uniq on the list to see which have only 1 entry (not 2). And AWK is a GREAT tool to do this

By: Carlo

Carlo — Wed, 14 Mar 2007 19:39:07 +0000

Random Guy:
try with
find folder_name -name *jpg

By: Random Guy

Random Guy — Wed, 14 Mar 2007 11:30:54 +0000

any idea how to make your example work on all subfolders within a directory also? i tried ls -R but it won’t work.

By: tannoiser

tannoiser — Sun, 18 Feb 2007 18:02:30 +0000

I know, Carlo, and your code is nice.
But to me, the correct answer is “don’t”. Use the appropriate tool, it’s often a good suggestion.

(of course, this is for the original “researcher”… :))

By: Carlo

Carlo — Sat, 17 Feb 2007 16:05:19 +0000

Good answer but the original problem was about using AWK

By: tannoiser

tannoiser — Sat, 17 Feb 2007 13:47:26 +0000

*cough*

rename ’s/\.jpg$//’ *.jpg